Question

Suppose f varies inversely with g and that f = 45 when g = 6 . What is the value of f when g = 9?

Answer 1

`30`

Explanation:

Given
`fprop 1/g`
or `f_1 .g_1=f_2 .g_2` ......(1)
Let the required value of `f=x`
Inserting in equation (1)
`45xx6=x xx9`
Solving for `x`
`x=(cancel(45)^5xx6)/cancel9_1=30`