Question

How do you factor `16n^2+ 43n -15`?

Answer 1

`(16n-5)(n+3)`

Explanation:

Any quadratic that can be factored can be expressed in the general form `(ax+b)(cx+d) = acx^2 +(ad+bd)x +bd`

We therefore need to find factors of `16` and `-15` that in the right combination will give `43`

`16 =16*1` and `15 =5*3`

`3*16 = 48`

`48-5*1=43`

`:.16n^2+43n-15 = (16n-5)(n+3)`