Question

How do you solve the following system?: `-2x -8y =3, 3x -2y = -3`

Answer 1

To substitute, we need to solve for one of the variables and then substitute this into the other equation.

Explanation:

`-2x = 3 + 8y`

`x = -3/2 - 4y`

`:. 3(-3/2 - 4y) - 2y = -3`

`-9/2 - 12y - 2y = -3`

`-14y = -3 + 9/2`

`-14y = 3/2`

`y = (3/2)/-14`

`y = -3/28`

Solving for x:

`3x - 2(-3/28) = -3`

`3x + 6/28 = -3`

`3x = -3 - 3/14`

`3x = -42/14 - 3/14`

`3x = -45/14`

`x = -45/42`

`x = -15/14`

Therefore, the solution set is `{-15/14, -3/28}`. Don't forget solutions always have to be presented in the form `{x, y}`.

Hopefully this helps!