Question

How do you find the definite integral for: `x^2 + x + 4` for the intervals [0,2]?

Answer 1

`38/3`

Explanation:

To integrate this function use the `color(blue)"power rule"`

`int(ax^n)dx=(ax^(n+1))/(n+1)` which can be applied to each term.

`rArrint_0^2(x^2+x+4)dx=[x^3/3+x^2/2+4x]_0^2`

now subtract the value of the lower limit from the value of the upper limit.

`rArr(8/3+2+8)-(0)=38/3`