The product of two consecutive integers is 80 more than 15 times the larger integer. What are the integers?

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Answer 1 · 2016-06-01T23:41:42

#19,20# or #-5,-4#

Let the larger integer be #n#.

Then we are told:

#(n-1)n = 15n+80#

Subtract #15n# from both sides to get:

#(n-16)n = 80#

So we are looking for a pair of factors of #80# which differ by #16#.

The pair #20, 4# works.

Hence #n=20# or #n=-4#

So the two consecutive integers are #19,20# or #-5,-4#