Question

How do you solve `(x-2)(x+5) = 18`?

Answer 1

`x = 4`, `x = -7`

Explanation:

`(x - 2)(x + 5) = 18`

`=> x^2 + 3x - 10 = 18`

`=> x^2 + 3x - 28 = 0`

`=> (x + 7)(x - 4)` = 0

`=> x + 7 = 0 => x = -7`
`=> x - 4 = 0 => x = 4`