Question

How do you solve `6y - x = -36` and `y = -3x` using substitution?

Answer 1

`x=36/19`
`y=-108/19`

Explanation:

if `y=-3x` let's substitute in the first equation, so:
`6(-3x)-x=-36`
then
`-18x-x=-36`
`-19x=-36`
`x=36/19`

and
`y=-3(36/19)`
`y=-108/19`