How do you find the slope of the secant lines of #f(x) = 7x^2# at #(4, f(4))# and #(4+h, f(4+h))#?
1 Answer
Jun 5, 2016
Explanation:
Find the points at
#f(4)=7(4)^2=7(16)=112#
#f(4+h)=7(4+h)^2=7(16+8h+h^2)=112+56h+7h^2#
The slope of the secant line is the slope of the line connecting the points
The slope is
#m=((112+56h+7h^2)-112)/((4+h)-4)=(56h+7h^2)/h=56+7h#