How do you use the important points to sketch the graph of #y=1/8x^2#?

1 Answer
Jun 7, 2016

Put values of x in the equation and get the corresponding y values. You will get a parabolic graph. You could take points such as 0,-4,4,-8,8, etc.

Explanation:

Make a table of 'x' versus 'y'. Now put values of x and find corresponding values for y. In your question, we can start be putting x = 0, hence , y = #(1/8)*0 = 0#

x = 4, hence , y = #(1/8)*4^2 = 2#

x = -4, hence , y = #(1/8)*((-4)^2) = 2#

You have to be wise while choosing the values of x to put into the equation so that you get whole number values for y.
graph{(1/8)*x^2 [-10, 10, -5, 5]}