How do you differentiate #f(x)=(3x)/(x-2)-6/(x-2)# using the quotient rule?
1 Answer
Jun 7, 2016
#dy/dx=0#
Explanation:
Given -
#y=(3x)/(x-2)-6/(x-2)#
Since
#y=(3x-6)/(x-2)#
#dy/dx=([(x-2)(3)]-[(3x-6)(1)])/(x-2)^2#
#dy/dx=([3x-6]-[3x-6])/(x-2)^2#
#dy/dx=(3x-6-3x+6)/(x-2)^2#
#dy/dx=0/(x-2)^2=0#
