A technician charges an initial fee of $300 plus an hourly fee of $60. Mr. Jenks paid the technician $480. How many hours did the technician work?

2 Answers
Jun 8, 2016

This translates to the equation #f=$300+hxx$60=$480#

Explanation:

Where #f=#total amount and #h=#number of hours.

Subtract the inital fee #$300# from the total:

#hxx$60=$180->h=($180)/($60)=3# hours

Jun 8, 2016

Technician worked for #3# hours.

Explanation:

Assume that the technician worked for #x# hours.

As he charges initial fee of #$300# plus an hourly fee of #$60#, his charges for #x# hours would be

#300+60x#

As Mr. Jenks paid #$480#,

#300+60x=480#

or #60x=480-300=180#

or #x=180/60=3#

Hence technician worked for #3# hours