Question

Question #09e1e

Answer 1

No 34 simplifies to 1

Explanation:

We make use of the following 'trig identities'

`•cottheta=(costheta)/(sintheta)`

• cos (angle) = sin (complement)

• sin (angle) = cos (complement)

Note Complementary angles are 2 angles whose sum is `90^@`

The complement of `60^@" is" (90-60)^@=30^@`

and so `cos60^@=sin30^@`

`rArrcos(90-theta)=sintheta" and" sin(90-theta)=costheta`

Substituting these identities into the question gives.

`((costheta)/(sintheta).sintheta)/costheta=((costheta)/cancel(sintheta).cancel(sintheta))/costheta=costheta/costheta=1`