How do you fully simplify #sqrt(8x^19y^36#?

1 Answer
Jun 8, 2016

#sqrt(8x^19y^36)=2x^9y^18sqrt(2x)#

Explanation:

#sqrt(8x^19y^36)=sqrt(2^3x^19y^36)#

We know that square root of an even power of number is easy to get as #sqrt(x^(2n))=x^n#, but here we have odd powers of #2# and #x# and hence we break it as follows.

#sqrt(2^3x^19y^36)=sqrt(2^2x^18y^36xx2x)#

= #sqrt(2^2x^18y^36)xxsqrt(2x)#

= #2x^9y^18sqrt(2x)#