How do you solve $(e^3)^(2x) = (e^3)(e^(2x))$ ?

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Answer 1 · 2016-06-08T14:02:27

$x = 3/4$

$(e^3)^{2x} = e^{3 xx 2x} = e^{6x}$

so

$e^{6x}= e^{4x}e^{2x} = (e^3)(e^{2x})$

then

$(e^{4x}-e^3)e^{2x} =0$

but

$e^{2x} > 0$

so

$e^{4x}=e^3->4x=3->x = 3/4$

How do you solve (e^3)^(2x) = (e^3)(e^(2x))(e^3)^(2x) = (e^3)(e^(2x))?