What is the equation of the line passing through #(5,4)# and #(-9,-2)#?

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Answer 1 · 2016-06-09T09:39:11

The equation of the straight line is : # 7y - 3x + 11 =0 #

Let #A(x1,y1) = A(5,4)#
and #B(x2,y2) = B(-9,-2)#

First find the slope of the line, using the formula :

# m = (y2-y1)/(x2-x1) #

# m = (-6)/-14 = 3/7 #

Now using the point-slope form of a straight line :
# y-y1=m(x-x1)#

#y-4=3/7*(x-5) #

On simplifying, we get,
# 7y - 3x + 11 =0 #

graph{3/7*(x-5) +4 [-10, 10, -5, 5]}