How do you write #2.22 times 10 ^ -6# in standard notation?

1 Answer
Jun 11, 2016

In standard notation #2.22xx10^(-6)=0.00000222#

Explanation:

In scientific notation, we write a number so that it has single digit to the left of decimal sign and is multiplied by an integer power of #10#.

In other words, in scientific notation, a number is written as #axx10^n#, where #1<=a<10# and #n# is an integer and #1<=a<10#.

To write the number in normal or standard notation one just needs to multiply (or divide if #n# is negative). This means moving decimal #n# digits to right if multiplying by #10^n# and moving decimal #n# digits to left if dividing by #10^n# (i.e. multiplying by #10^(-n)#).

In the given case, as we have the number as #2.22xx10^(-6)#, we need to move decimal digit to the left by six points. For this, let us write #2.22# as #0000002.22# and moving decimal point six points to left means #0.00000222#

Hence in standard notation #2.22xx10^(-6)=0.00000222#