What is the sum of interior angles in a hexagon?

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Answer 1 · 2016-06-10T21:27:08

$120^0$

Hexagon is 6 sided. Think it as 6 triangles. so at the centre we have each triangles vertex being: $360/6 = 60^0$

The sum of internal angles in a triangle is $180^0$ which means that the other two angles sum to $180-60 = 120^0$

We have 6 of these $120^0$ so the sum of the interior angles is

$6xx120= 720^0$

Answer 2 · 2016-06-11T17:14:06

$720^@$ i.e. $4pi$ radians

No matter how irregular the hexagon, it can always be dissected into $4$ triangles.

For example:

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Each of the $4$ triangles has interior angles summing to $180^@$ - i.e. $pi$ radians.

The interior angles of the hexagon are the sum of the interior angles of the constituent triangles, so sum to:

$4 * 180^@ = 720^@$ or $4pi$ radians.