Question

How do you find the center and radius of the circle `(x-5) ^2 + (y+3) ^2 = 16`?

Answer 1

Centre `(5,-3)`, Radius `= 4.`

Explanation:

We know that the equation (eqn.) of a circle having centre at point (pt.) `(h,k)` & radius `r` is given by `(x-h)^2+(y-k)^2=r^2.`

Comparing this with the given eqn., we get centre at the pt. `( 5,-3)` and radius `r=4.`