Question

How do you simplify `sqrt8/sqrt6`?

Answer 1

`sqrt8/sqrt6=(2sqrt3)/3`

Explanation:

`sqrt8/sqrt6=sqrt((2xx2xx2)/(2xx3))`

= `sqrt((2xx2xxcancel2)/(cancel2xx3))`

= `2/sqrt3xxsqrt3/sqrt3`

= `(2sqrt3)/3`