How do you simplify #(5xy)^0#?

1 Answer

Anything taken to the power 0 equals 1, so we have #(5xy)^0=1#

Explanation:

The key here is to work this through with PEMDAS:

Parentheses
Exponents
Multiplication
Division
Addition
Subtraction

Starting with the original:

#(5xy)^0#

There are no operations in the Parentheses that we can do (there is multiplication but it's as simplified as we can make it, so there is nothing further to be done), so we move on to the Exponents.

Looking at the expression, we have a value #(5xy)# being taken to the 0 power. Anything taken to the 0 power is equal to 1, so the final answer here is

#(5xy)^0=1#