How do you calculate #log_2 8#?

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Answer 1 · 2016-06-19T04:35:38

#log_2 8=3#

Let #x# be the unknown value

#x=log_2 8#

also

Using exponential form

#2^x=8#

#2^x=2^3#

and

#x=3#

God bless...I hope the explanation is useful.