How do you solve #((2t-1)/(3t+4)) = 2#?

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Answer 1 · 2016-06-19T09:00:15

#color(green)(t = -9/4#

#(2t - 1) / (3t + 4) = 2#

#(2t - 1) = color(blue)(2) * (3t + 4 )#

#color(blue)(2)# is multiplied with both terms within the second bracket.

#(2t - 1) = color(blue)(2) * (3t) + color(blue)(2) *( 4 )#

#2t - 1 = 6t + 8#

#2t - 6t = 8 +1 #

# - 4t = 9 #

# -t = 9/ (-4) #

#color(green)(t = -9/4#