Question

How many moles of oxygen are produced by the decomposition of six moles of potassium chlorate in the reaction `2KClO_3 -> 2KCl + 3O_2`?

Answer 1

`KClO_3(g) + Deltararr KCl(s) + 3/2O_2(g)`

Explanation:

From the equation, `3/2` equiv dixoygen gas evolve from `1` equiv chlorate.

You started with `6` equiv chlorate, and thus `9` equiv dioxygen gas are evolved. This is a common undergrad experiment. I think you need to add some sort of manganese oxide catalyst.