Question

What is the integral of `cos^2(6x) dx`?

Answer 1

`:. intcos^2(6x)dx=(1/2)(x+(sin12x)/12)+C.`

Explanation:

Recall that `cos^2theta=(1+cos2theta)/2.`

`:. cos^2(6x)=(1+cos12x)/2.`

`:. intcos^2(6x)dx=int(1+cos12x)/2dx=(1/2){x+(sin12x)/12}+C.`