What is the mass in grams of #1.02 * 10^24# atoms manganese?

1 Answer
anor277
Jun 21, 2016

One mole of stuff represents #6.022140857(74)xx10^23# individual items of that stuff.

Explanation:

#1# #mol# of manganese has a mass of #54.94*g#.
Thus, #"Mass"#
#=(1.02xx10^24" atoms manganese")/(6.022xx10^24" atoms of manganese "mol^-1)xx54.94*g*mol^-1#

#~=9.0*g#

Related questions
See all questions in The Mole
Impact of this question
13914 views around the world
You can reuse this answer
Creative Commons License