How do you determine if #y= 5^(3 + 2x)# is an even or odd function?

1 Answer
Jun 21, 2016

This function is not even and is not odd.

Explanation:

by definition, an even function is a function that does not change if instead of #x# we use #-x#. An odd function changes the sign when #x# is swapped with #-x#.

Then let's try

#y=5^(3+2x)#

and we substitute
#x->-x#

#y=5^(3-2x)#

The two functions are clearly different.
For example, when #x=1# we have

#y=5^(3+2)=5^5#

and for #x=-1#

#y=5^(3-2)=5^1=5#.

The function does not stay unchanged neither it swaps the sign.
The function is not even and is not odd.