Question

For what values of x, if any, does `f(x) = 1/((2x-2)(5x-4)` have vertical asymptotes?

Answer 1

`x=1` or `x = 4/5`

Explanation:

you will have vertical asymptotes when you have a zero in the denominator, ie when you are dividing by zero.

here that occurs when `2x - 2 = 0` and `5x - 4 = 0` ie when `x=1` or `x = 4/5`