How do you graph #2x-y=4#?

1 Answer
Jun 22, 2016

Calculate a few coordinate points that satisfy the given equation;
plot those points;
draw a line through the plotted points.

Explanation:

Given #2x-y=4#

And picking some (arbitrary) #x# values (#x in {0,1,2}#)

We can solve for #y# using these values of #x#
#{: (underline(x),,underline(y)), (0,rarr,-4), (1,rarr,-2), (2,rarr,0) :}#

which provides the coordinates #(x,y) in {(0,-4), (1,-2), (2,0)}#

Plotting these points and drawing a line through them:
graph{(x^2+(y+4)^2-0.02)((x-1)^2+(y+2)^2-0.02)((x-2)^2+y^2-0.02)(2x-y-4)=0 [-6.784, 9.02, -5.576, 2.33]}