Question

How do you solve `4x^2 - 12x + 9 = 0`?

Answer 1

`x=3/2`

Explanation:

In `4x^2-12x+9=0` as niddle term `-12x` is twice the product (with negative sign) of square roots of first (`sqt(4x^2)=2x`) and third term (`sqrt9=3`,

it can be factorized using formula `a^2-2ab+b^2=(a-b)^2`

Hence `4x^2-12x+9=0`

`hArr(2x)^2-2xx3xx3x+3^2=0`

or `(2x-3)^2=0`

and hence `2x=3` or `x=3/2`