Question

Question #7396d

Answer 1

Option=1

Explanation:

`ZnCl_2" dissolves in excess NaOH"`
`"as well as in excess "NH_3`

In aqueous solution the reactions occuring can be represented by following equations.

For `NaOH`

`ZnCl_2(aq)+2NaOH(aq)=Zn(OH)_2darr+2NaCl(aq)`

`Zn(OH)_2+2NaOH(aq)=Na_2ZnO_2("soluble")+2H_2O`

For `NH_3(aq)=NH_4OH`

`ZnCl_2(aq)+2NH_4OH(aq)=Zn(OH)_2darr+2NH_4Cl(aq)`

`Zn(OH)_2+4NH_4OH(aq)=Zn(NH_3)_4(OH)_2("soluble")+4H_2O`