Question

`g(n) = 3n + 2` and `f(n) = 2n^2 + 5` What is `g(f(2))`?

Answer 1

`g(f(2))=41`

Explanation:

`f(2)=2(2^2)+5= 13`

So `g(f(2))->g(n=13)`

`g(n=13)->3(13)+2 = 41`