Question

How do you solve `abs(2z -3) = 4z - 1`?

Answer 1

`x=3/2`

Explanation:

It is equivalent to:

`(2z-3>=0 and 2z-3=4z-1) or (2z-3<0 and -2z+3=4z-1)`

`(z>=3/2 and 2z=-2) or (z<3/2 and 6z=4)`

`(z>=3/2 and z=-1) or (z<3/2 and z=2/3)`

the first condition is impossible, then since `2/3<3/2`:

the solution is `x=3/2`