Question

How do you find the equation of the circle given Center (5,0), r=12?

Answer 1

`x^2+y^2-10x-119=0`

Explanation:

The equation of the circle, when you know center and radius, is

`(x-x_0)^2+(y-y_0)^2=r^2`

So

`(x-5)^2+y^2=12^2`

`x^2-10x+25+y^2-144=0`

`x^2+y^2-10x-119=0`