How do you find #P^2# given #P=((3, 1), (1, 3))#? Precalculus Matrix Algebra Multiplication of Matrices 1 Answer EZ as pi Jun 25, 2016 #P^2=((10, 6), (6, 10))# Explanation: #P^2# means multiply the matrix by itself, following the usual method for multiplying matrices. #P^2 =((3, 1), (1, 3))((3, 1), (1, 3))# #= ((3xx3+1xx1, 3xx1+1xx3), (1xx3+3xx1, 1xx1+3xx3))# #=((10, 6), (6, 10))# Answer link Related questions What is multiplication of matrices? How do I do multiplication of matrices? What is scalar multiplication of matrices? What are some sample matrix multiplication problems? How do I multiply the matrix #((6, 4, 24),(1, -9, 8))# by 4? How do I multiply the matrix #((3, 0, -19),(0, 7, 1), (1, 1/5, 2/3))# by -6? How do I multiply the matrix #((6, 4, 24),(1, -9, 8))# by the matrix #((1, 5, 0), (3, -6, 2))#? Is matrix multiplication associative? If #A=((-4, 5),(3, 2))# and #B=((-6, 2), (1/2, 3/4))#, what is #AB#? In matrix multiplication, does ABC=ACB? See all questions in Multiplication of Matrices Impact of this question 1486 views around the world You can reuse this answer Creative Commons License