Question

How do you solve for the voltages and currents in this circuit diagram?

Answer 1

Please see below.

Explanation:

As `R_1` and `R_2` are in parallel, the resultant resistance `R` will be given by `1/(R_1)+1/(R_2)`.

Hence `1/R=1/3+1/6=1/2` and hence `R=2` `Omega`.

As the voltage of battery source is `120V`, assuming `0` internal resistance, current passing through circuit or `R_3` is `I_0=120/(15+2)=120/17=7 1/17` ampere.

and hence voltage `V_3` across it will be `120/17xx15=1800/17= 105 15/17V`

and that across other two resistances i.e. `V_1=V_2` will be `120-1800/17=240/17V` each.

Hence current `I-1` passing through `R_1` is `240/17xx1/3=80/17=4 12/17` ampere.

and current passing `I_2` through `R_2` is `240/17xx1/2=120/17=7 1/17` ampere.