Question

How do you convert `(-3, 3)` to polar form?

Answer 1

`(3sqrt2, (3pi)/4)`

Explanation:

The given

`x=-3` and `y=3`

`r=sqrt(x^2+y^2)=sqrt((-3)^2+(3)^2)=sqrt(9(2))=3sqrt2`

`theta=arctan(y/x)=arctan(3/(-3))=arctan(-1)=(3pi)/4`

God bless....I hope the explanation is useful.