How do you solve #(x- 5/2) ^2 = 9/4#?

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Answer 1 · 2016-06-27T12:45:46

#x = 4 or x = 1#

Find the square root of both sides, remembering that there can be a positive or negative root.

#(x - 5/2)^2 = 9/4#

#sqrt((x - 5/2)^2) = +-sqrt(9/4)#

#x - 5/2 = 3/2 " or " x -5/2 = -3/2#

#x = 3/2+5/2 " or " x = -3/2+5/2#

#x = 8/2 " or "x = 2/2#

#x = 4 or x = 1#