How do you write an equation for a circle with center(4,7) and passing through (3,-2)?

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Answer 1 · 2016-06-29T15:27:36

#(x-4)^2+(y-7)^2=82#

Using the center - radius form

#(x-h)^2+(y-k)^2=r^2#

The radius #r# may be computed using the center and the given point

#r=sqrt((7--2)^2+(4-3)^2)#

#r=sqrt82#

Let us formulate the equation

#(x-h)^2+(y-k)^2=r^2#

#(x-4)^2+(y-7)^2=(sqrt(82))^2#

#(x-4)^2+(y-7)^2=82#

God bless....I hope the explanation is useful.