Question

How do you factor `6abc^(2) - 14a^(2)bc + 4ab^(2)c`?

Answer 1

`2abc(3c-7a+2b)`

Explanation:

Always look for a common factor first.
There is a common factor of `2abc` which can be divided out of each term.

`6abc^(2) - 14a^(2)bc + 4ab^(2)c`

=`2abc(3c-7a+2b)`