Question

How do you find the limit of `f(x)= 1/x^2` as x approaches infinity?

Answer 1

`lim_(x->oo) 1/(x^2) = 0`

Explanation:

As x tends to infinity, the numerator will remain constant. Basically this means we have

`1/(lim_(x->oo) x^2)`

In this limit, we will tend towards `1/(oo)^2` which obviously tends to zero. Hence limit is zero.