How do you graph the line #2x-3y=0#?

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Answer 1 · 2016-07-03T02:50:13

Solve for #y#

#2x-3y=0#

#2x=3y#

#y=2/3x#

Consider #y=mx+b# where m is the slope and b is the y-intercept

graph{2/3x [-4.178, 5.824, -2.35, 2.65]}

The #y#-intercept is #0# so there is a point at #0,0#.

The slope is #2/3# so start from #0# and move up #2# and to the right #3# and there is another point. Draw a straight line through these points. .