How do you find the center and radius of the circle #x^2 + y^2 – 8x – 6y – 75 = 0#?
1 Answer
Jul 4, 2016
Centre:
Radius:
Explanation:
Complete the square for
#0 = x^2+y^2-8x-6y-75#
#= (x^2-8x+16)+(y^2-6y+9)-100#
#= (x-4)^2+(y-3)^2-10^2#
Add
#(x-4)^2+(y-3)^2=10^2#
This is in the standard form of the equation of a circle:
#(x-h)^2+(y-k)^2=r^2#
where