Question

How do you find the exact value of `sin^-1(sin(pi/6))`?

Answer 1

`pi/6.`

Explanation:

If `f^-1` is the inverse fun. of a fun.`f`, then, by defn., `f^-1of(x)=f^-1(f(x)=x` and, `fof^-1(x)=f(f^-1(x)=x.`

Clearly, `sin^-1(sin(pi/6))=pi/6`

Otherwise
Recall that #sin(pi/6)=1/2. #sin^-1(sin(pi/6)) = sin^-1(1/2)=pi/6#

Is ihts OK? Enjoy Maths.!.