How do you simplify #(2sqrt3+3sqrt2)(3sqrt3 -sqrt2)#?

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Answer 1 · 2016-07-06T09:30:46

#12+7sqrt6#

#(2sqrt3+3sqrt2)(3sqrt3 -sqrt2)#

Each term in the first bracket has to be multiplied by each term in the other bracket.

Note: #sqrt3xxsqrt3 = sqrt3^2 = 3#

#(6sqrt3xxsqrt3) - (2sqrt3xxsqrt2) + (9sqrt2sqrt3) -(3sqrt2xxsqrt2)#

#6xx3 + (- 2sqrt6 + 9sqrt6) -3 xx2#

#18+7sqrt6 -6#

#12+7sqrt6#