The figure above shown the position of the force vector whose #x# and #y# components are to be resolved.
(a) the #x# scalar component #F_x=Fcos 39^@#
Inserting value of #cos# from tables
#=>F_x=Fxx0.7771= 592xx0.7771#
#=460.0N#, rounded to one decimal place.
(b) #y# scalar component of the vector #F_y=-Fsin 39^@#
(#-ve# sign has been placed in front as the angle is in the fourth quandrant or #F_y# is in the #-y# direction).
Inserting value of #sin# from tables
#=>F_y=Fxx0.6293=592xx0.6293#
#= 372.6N#, rounded to one decimal place.