Question

How do you write an equation of a line parallel to y= 3/2x-6 and passes through (-6,2)?

Answer 1

`y=3/2x+11`

Explanation:

The slope of this line is `3/2`; any line parallel to this one has the same slope.
You can use the following general equation and substitute the coordinates of the point (-6,2) in `(x_0,y_0)`:

`y-y_0=m(x-x_0)`

so that the requested equation is:

`y-2=3/2(x+6)`

`y=3/2x+9+2`

`y=3/2x+11`