Question

Question #df0fe

Answer 1

It is `0.555` atm.

Explanation:

The equation of the perfect gas is

`PV=nRT`

`P` is the pressure that we want to calculate, `V` is the volume in `"m"^3`, `n` are the mols, `R` is the constant of perfect gas `8.314472 ("m"^3"Pa")/("mol" "K")`, `T` is the temperature in `"K"`.
First of all we need to transform our quantity in the proper units:

`V=11.2 "L"=11.2*10^-3 "m"^3`

`T=30^\circ"C"=30+273.15 "K"=303.15"K"`.

The pressure is

`P=(nRT)/V=(0.25 cancel"mol"*8.314472 (cancel("m"^3)"Pa")/(cancel"mol" cancel"K")*303.15cancel"K")/(11.2*10^-3 cancel("m"^3))`

`=(0.25* 8.314472*303.15)/(11.2)*10^3"Pa"`

`=56261.88" Pa"`, or, if we want in a more familiar unit, we can convert it in atm using the conversion `1"atm"=101325"Pa"` then

`56261.88" Pa"= 56261.88/101325" atm"`

`=0.555" atm"`.