How do you solve #(x-2)/2 <=3#?

1 Answer
Eric C.
Jul 7, 2016

#x <= 8#

Explanation:

Solve the equation the same way as a linear equation except at any stage if you multiply by a negative change the sign around. So..

#(x - 2)/2 <= 3#

Multiply both sides by 2, since we are multiplying by a positive leave the sign:

#x - 2 <= 6#

Then add 2 to both sides:

#x <= 8#

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