How do you solve x2+2y=22 and x2y=13?

2 Answers
Jul 7, 2016

y=13x2

y=13+x2

x2+2(13+x2)=22

x226+2x2=22

3x2=22+26

3x2=48

x2=16

x=±4

42y=13 and 42y=13

16y=13 and 16y=13

y=3andy=3

The solution set is therefore {4,3} and {4,3}.

Hopefully this helps!

Jul 7, 2016

x=±4
y=3

Explanation:

x2+2y=22
x2y=13
3y=9
y=3
x2=16
x=±4