How do you solve x^2+2y=22 and x^2-y=13?

2 Answers
Jul 7, 2016

-y = 13 - x^2

y = -13 + x^2

x^2 + 2(-13 + x^2) = 22

x^2 - 26 + 2x^2 = 22

3x^2 = 22 + 26

3x^2 = 48

x^2 = 16

x = +-4

4^2 - y = 13" and " -4^2 - y = 13

16 - y = 13" and "16 - y = 13

y = 3" and y = 3

The solution set is therefore {4, 3} and {-4, 3}.

Hopefully this helps!

Jul 7, 2016

x=+-4
y=3

Explanation:

x^2+2y=22
x^2-y=13
3y=9
y=3
x^2=16
x=+-4